Engineering
Physics
Radiation
Question

In Newton's law of cooling dθdt=−K(θ−θ0). The proportionality constant K is K1 and K2 for two substances A and B having mass m1 and m2, surface area A1 and A2, specific heat S1 and S2, emissivity e1 and e2 respectively, it is given that e1e2=1,  A1A2=1,  m1m2=2,  S1S2=13,, while surrounding temperature remain constant. If K1K2=12X then X is :

JEE Advance
College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Solution

As    K=4e A σT3ms