In the given circuit, charge Q2 on the 2μF capacitor changes as C is varied from 1μF to 3µF. Q2 as a function of ‘C’ is given properly by : (figures are drawn schematically and are not to scale.

Engineering

Physics

Circuit Analysis Having Capacitor Only

Question

In the given circuit, charge Q₂ on the 2μF capacitor changes as C is varied from 1μF to 3µF. Q₂ as a function of ‘C’ is given properly by : (figures are drawn schematically and are not to scale.

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$\frac{1}{C} = \frac{1}{C_{1}} + \frac{1}{C_{2}}$ Q = C V

$C = \frac{3 C}{3 + C}$

$Q = \frac{3 CE}{3 + C} Q_{2} = (\frac{3 CE}{3 + C}) \frac{2}{3} = \frac{2 CE}{3 + C}$

$Q_{2} = \frac{2 CE}{3 + C}$