In the radioactive change _{Z}^{A} P \overset{}{\rightarrow}_{Z + 1}^{\textrm{ }\textrm{ }\textrm{ }\textrm{ }\textrm{ } A} Q \overset{}{\rightarrow}_{Z - 1}^{A – 4} R \overset{}{\rightarrow}_{Z - 1}^{A – 4} S The radiations emitted in sequence are :

Foundation

Chemistry Foundation

Nuclear Chemistry

Question

In the radioactive change $_{Z}^{A} P {\overset{}{\to}}_{Z + 1}^{A} Q {\overset{}{\to}}_{Z - 1}^{A - 4} R {\overset{}{\to}}_{Z - 1}^{A - 4} S$ The radiations emitted in sequence are :

γ, α, γ

α, β, γ

β, γ, α

β, α, γ

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This represents a radioactive decay chain. Analyze each step's change in atomic number (Z) and mass number (A).

First decay: Z→Z+1, A unchanged. This is β⁻ decay (emits an electron).

Second decay: Z+1→Z-1, A→A-4. This is α decay (emits a helium nucleus, ${}^{2}{He} 4$ ).

Third decay: Z-1→Z-1, A-4 unchanged. This is γ decay (emits a photon).

Final Answer: β, α, γ