In the reaction, the product C is :

Engineering

Chemistry

Elimination Reactions

Oxidation of alcohol

Question

In the reaction, ${CH}_{3} COOH \overset{{LiAlH}_{4}}{\to} A \to_{}^{{PCl}_{5}} B \to_{}^{AlcKOH} C$ the product C is :

Acetylene

Ethylene

Acetaldehyde

Acetyl chloride

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This is a multi-step organic reaction sequence starting with acetic acid (CH₃COOH).

Step 1: Reduction with LiAlH₄. LiAlH₄ reduces carboxylic acids to primary alcohols. Therefore, compound A is ethanol: ${CH}_{3} {CH}_{2} OH$ .

Step 2: Reaction with PCl₅. PCl₅ converts alcohols to alkyl chlorides. Therefore, compound B is chloroethane: ${CH}_{3} {CH}_{2} Cl$ .

Step 3: Reaction with Alc. KOH. Alcoholic KOH causes dehydrohalogenation (elimination) of alkyl halides, forming alkenes. Chloroethane loses HCl to form ethylene.

Therefore, the final product C is ethylene.

Final Answer: Ethylene