In the reaction Na \textrm{ } \left(\right. s \left.\right) + \frac{1}{2} H

Engineering

Chemistry

Balancing of Redox Reaction

Question

In the reaction

$Na (s) + \frac{1}{2} H_{2} \to NaH$

‘Na’ as well as ‘H’ both undergo reduction

‘Na’ as well as ‘H’ both undergo oxidation

‘Na’ is reduced & ‘H’ is oxidised.

‘Na’ is oxidised & ‘H’ is reduced

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In the reaction $Na (s) + \frac{1}{2} H_{2} \to NaH$ , we analyze oxidation states to identify redox changes.

The oxidation state of elemental sodium, Na(s), is 0. In NaH, sodium has an oxidation state of +1. An increase in oxidation state signifies oxidation.

The oxidation state of hydrogen in H₂ is 0. In NaH, hydrogen has an oxidation state of -1. A decrease in oxidation state signifies reduction.

Therefore, 'Na' is oxidised and 'H' is reduced.

Final Answer: 'Na' is oxidised & 'H' is reduced