In the reaction, the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is :

Engineering

Chemistry

Intensive Extensive State and Path Function

Question

In the reaction,

the time taken for 75% reaction of P is twice the time taken for 50% reaction of P. The concentration of Q varies with reaction time as shown in the figure. The overall order of the reaction is :

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P + Q $\to$ R + S

Given : T_75% = 2 t_50% for P

$\Rightarrow$ Reaction is of first order w.r.t. P

$\Rightarrow$ From graph it is clear that reaction is of zero order w.r.t. Q

[Q]_t = [Q]₀ – kt

so overall order will be = 1 + 0 = 1.

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