In Young's double slit experiment, one of the slit is wider than other, so that the amplitude of the light from one slit is double of that from other slit. If Im be the maximum intensity, the resultant intensity I when they interfere at phase difference f is given by :

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In Young's double slit experiment, one of the slit is wider than other, so that the amplitude of the light from one slit is double of that from other slit. If I_m be the maximum intensity, the resultant intensity I when they interfere at phase difference f is given by :

$\frac{I_{m}}{5} (1 + 4 \cos^{2} \frac{ϕ}{2})$

$\frac{I_{m}}{9} (1 + 8 \cos^{2} \frac{ϕ}{2})$

$\frac{I_{m}}{9} (4 + 5 cosϕ)$

$\frac{I_{m}}{3} (1 + 2 \cos^{2} \frac{ϕ}{2})$

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I₀ and 4I₀

I_m = 9I₀

I_res = I₀ + 4I₀ + 2 $\sqrt{4 I_{0}^{2}} cosθ$

= 5I₀ + 4I₀ cos $ϕ$

$= \frac{I_{m}}{9} (1 + 8 \cos^{2} \frac{ϕ}{2})$