Engineering
Mathematics
Question

Let A=1    0    02    1    03    2    1,U1,U2 and U3 be column matrices satisfying AU1=[100],AU2=[236],AU3=[231]. If U is 3 × 3 matrix, whose columns are U1, U2, U3. then |U| is 

– 11

– 3

32

2

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Solution
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A=1    0    02    1    03    2    1

A–1 = ?

|A| = 1(1 – 0) – 0 + 0

= 1 

A=1    2    30    1    20    0    1

AdjA=100210121

A1=1|A|AdjA

=100210121

U1=100100210121

=121

U2=236100210121

=24+3+0026+6

=212

U3=231100210121

=24+326+1=213

|U|=122211123

= 1(3 + 2) – 2(6 + 1) – 2(– 4 + 1)

= 5 – 14 + 6

= – 3