Engineering
Mathematics
Locus of a Point
Question
Let ABCD be a square of two of whose adjacent vertices say A, B are on the positive x‑axis and y‑axis respectively. If C has co‑ordinates (4, 7), then area of ABCD is
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Solution
AB = a, PC = 4 = asin θ ......(1)
OB = asin θ, PB = a sin θ
OP = 7 = asin θ + acos θ
⇒ acos θ = 3, asin θ = 4
⇒ area = a2 = 32 + 42 = 25.