Engineering
Mathematics
Inverse of a Function
Question

Let a bijective function g : R → R  be defined as g(x) = {x+α2+2,   x27+αx,           x>2. If graph of y = f(x) is reflection of graph of y = g(x) w.r.t. line y = x, then find  f(11).

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Solution

For  g(x) to be bijective
Clearly    α > 0
and    4 + α2 = 7 + 2α
⇒     α2 – 2α – 3 = 0
⇒     (α – 3)(α + 1) = 0


g(x)={x+11,x23x+7,   x>2
f (x) is inverse of g(x) 
and  f (11) = g–1(11)
and  g(x) = 11  ⇒  x = 0  ⇒  g–1(11) = 0