Let a bijective function g : R → R be defined as g(x) = . If graph of y = f(x) is reflection of graph of y = g(x) w.r.t. line y = x, then find f(11).
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For g(x) to be bijective
Clearly α > 0
and 4 + α2 = 7 + 2α
⇒ α2 – 2α – 3 = 0
⇒ (α – 3)(α + 1) = 0

f (x) is inverse of g(x)
and f (11) = g–1(11)
and g(x) = 11 ⇒ x = 0 ⇒ g–1(11) = 0