Let f be a function defined on R (the set of all real numbers) such that
f '(x) = 2010(x - 2009)(x - 2010)2(x - 2011)3 (x - 2012)4, for all x ∈ R.
If g is a function defined on R with values in the interval (0, ∞) such that
f(x) = ln (g (x)), for all x ∈ R,
then the number of points in R at which g has a local maximum is
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g (x) = ef (x)
g ' (cx) = ef (x) f ' (x)
f ' (x) = 2010 (x – 2009)(x – 2010)2(x – 2011)3(x – 2012)4
g ' (x) = 0 x = 2009, 2010, 2011, 2012
for max. g ' (x) must change sign from + ve to – ve
x = 2009
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