Let f (x) = x2 and g(x) = sin x for all x ∈ R. Then the set of all x satisfying
(f o g o g o f ) (x) = (g o g o f) (x), where (f o g) (x) = f (g(x)), is
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gof(x) = gf(x) = g(x2) = sin x2
Go (gof(x)) = g(sin x2) = sin (sin x2)
Fo(gogof(x)) = f(sin (sin x2)) = (sin(sin x2))2
(sin (sin x2))2 = sin (sin x2)
Sin (sin x2) (sin (sin x2) –1) = 0
Sin (sin x2) = 0 or sin (sin x2) = 1
Sin x2 = np sin x2 = 2np +
At n = 0 At n = 0
Sin x2 = 0
x2 = n Not possible
n {0, 1, 2, …..}