Let f (x + y) = f (x) f (y), and f (1) = 2. For a ABC, a = f (3), b = f (1) + f (3) and c = f (2) + f (3).
If r, r1, r2, r3 radii of incircle and excircles according to their usual notations then
| Column - I | Column - II |
| (P) r | (1) |
| (Q) r1 | (2) |
| (R) r2 | (3) |
| (S) r3 | (4) |
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Putting x = y = 1, f (2) = 22 = 4
x = 2, y = 1, f (3) = 23 = 8
a = 8, b = 10, c = 12
s – b = 5, s – c = 3