Let f(x) be a polynomial of degree four having extreme values at x = 1 and x = 2. If = 3, then f(2) is equal to
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We have
∴ f (x) = (ax4 + bx3 + 2x2)
Now, f ' (1) = 0 ⇒ 4a + 3b = – 4
and f' (2) = 0 ⇒ 8a + 3b = – 2
∴ we get, a = , b = – 2
So, f (2) = 0