Let [ε0] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then :

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Let [ε₀] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then :

[ε₀] = [M^–1L²T^–1A]

[ε₀] = [M^–1L^–3T⁴A²]

[ε₀] = [M^–1L²T^–1A^–2]

[ε₀] = [M^–1L^–3T²A]

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$M^{1} L^{1} T^{- 2} \frac{I^{2} T^{2}}{[ε_{0}] L^{2}}$

$[ε_{0}] = \frac{I^{2} T^{2} L^{- 2}}{M^{1} L^{1} T^{- 2}}$

[ε₀] = M^–1L–3T⁴I²