Let L be a normal to the parabola y2 = 4x. If L passes through the point (9, 6), then L is given by
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y = mx – 2m – m3
It passes through (9, 6)
6 = 9m –2m – 2m – m3
m3 – 7m 6 = 0
(m – 1) (m – 2) (m + 3) = 0
m = –3, 1, 2
Hence equation will be
y = x – 3, y = 2x – 12 and y = –3x + 33