Let n1 < n2 < n3 < n4 < n5 be positive integers such that n1 + n2 + n3 + n4 + n5 = 20. Then the number of such distinct arrangements (n1, n2, n3, n4, n5) is
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(n1 = 1, n2 = 2, n3 = 3, n4 = 5, n5 = 9)
(n1 = 1, n2 = 2, n3 = 3, n4 = 6, n5 = 8)
(n1 = 1, n2 = 2, n3 = 4, n4 = 5, n5 = 8)
(n1 = 1, n2 = 2, n3 = 4, n4 = 6, n5 = 7)
(n1 = 1, n2 = 3, n3 = 4, n4 = 5, n5 = 7)
(n1 = 2, n2 = 3, n3 = 4, n4 = 5, n5 = 6)
(n1 = 1, n2 = 2, n3 = 3, n4 = 4, n5 = 10)