Engineering
Mathematics
Inverse of a Matrix
Question

Let P and Q be 3 × 3 matrices with PQ. If P3 = Q3 and P2Q = Q2P, then determinant of (P2 + Q2) is equal to :

1

0

–2

–1

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Solution

P3 = Q3

P2Q = Q2P

P3 – P2Q = Q3 – Q2P

P2 (P – Q) = Q2 (Q – P)

(P2 + Q2) (P – Q) = 0

| P2 + Q2 | | P – Q | = 0

| P2 + Q2 | = 0 or | P – Q | = 0.