Engineering
Mathematics
Definition of Trigonometric Ratio
Question

Let P={θ:sinθcosθ=2cosθ} and Q={θ:sinθ+cosθ=2sinθ} be two sets. Then

P = Q

 P ⊂ Q and Q – P ≢ Q

  QP

PQ

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Solution

 P:sinθcosθ=2cosθ

 sinθ=(2+1)cosθ

 tanθ=2+1

 tanθ=tan6712°

 θ=+3π8,nI                    .....................(1)

 Q:sinθ+cosθ=2sinθ

cosθ=(21)sinθ

 tanθ=121=2+1

 θ=+3π8,nI                     ...............(2)

  P = Q