Let PS be the median of the triangle with vertices P(2, 2), Q(6, – 1) and R (7, 3). The equation of the line passing through (1,

Engineering

Mathematics

Various Form of a Straight Line

Question

Let PS be the median of the triangle with vertices P(2, 2), Q(6, – 1) and R (7, 3). The equation of the line passing through (1, – 1) and parallel to PS is

4x + 7y + 3 = 0

4x – 7y – 11 = 0

2x + 9y + 7 = 0

2x – 9y – 11 = 0

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$S (\frac{13}{2}, 1)$

$m_{PS} = \frac{2 - 1}{2 - \frac{13}{2}} = \frac{1}{- 9 / 2} = \frac{- 2}{9}$

So, equation of line is

$(y + 1) = \frac{- 2}{9} (x - 1)$

⇒ 9y + 9 = – 2x + 2

⇒ 2x + 9y + 7 = 0.