Engineering
Physics
Physical Quantities
Question

Let the x – z plane be the boundary between two transparent media. Medium 1 in z ≥ 0 has a refractive index of 2 and medium 2 with z < 0 has a refractive index of 3. A ray of light in medium 1 given by the vector A=63i^+83j^10k^ is incident on the plane of separation. The angle of refraction in medium 2 is :

45°

60°

30°

75°

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Solution
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X–Y Plane        

µ1sinθ1 = µ2sinθ2

cosθ1=10(63)2+(83)2+100=10400=1020 

cosθ1=12

2sin60=3sinθ2

2×32=3sinθ2

sinθ2=12

θ2 = 45º

  

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