Let X = {1, 2, 3, 4, 5}. The number of different ordered pairs (Y, Z) that can be formed such that Y ⊆ X, Z ⊆ X, and Y ⋂ Z is empty, is :
Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.
Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA
1 can be distributed in two set Y and Z by 3 ways.
2 can be distributed in two set Y and Z by 3 ways.
3 can be distributed in two set Y and Z by 3 ways.
4 can be distributed in two set Y and Z by 3 ways.
5 can be distributed in two set Y and Z by 3 ways.
(The three ways are either only in Y or only in Z or in none of Y and Z.)
∴ Number of way of distributing each element = 35.
Please subscribe our Youtube channel to unlock this solution.