Engineering
Mathematics
Successive Differentiation
Question

Let y = sin 2t and ze–t = 1 where t be the parameter. If d2ydz2 = – ae–bt (cos 2t + c sin 2t), a, b, c  N then find (a + b + c).

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Solution

y = sin 2t,  z = et
dytdzt=2cos2tet = 2 e–t cos 2t
d2ydz2=ddt(2etcos2t)  ×  dtdz
=(2etcos2t4etsin2t)et
= – 2(e–2t cos 2t + 2e–2t sin 2t)
    a = 2, b = 2, c = 2
    a + b +  c = 6