Engineering
Mathematics
Linear Differential Equation
Question

Let y(x) be the solution of the differential equation (x log x) dydx+ y = 2x log x, (x 1). Then y(e) is equal to

2e

0

2

e

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Solution

Integrating factor = ℓn x

 General solution is

y (ℓn x) = 2(x ℓn x – x) + c

Put x = 1, we get c = 2

y(e) = 2