Engineering
Mathematics
Introduction to Complex Number
Question

Let z be a complex number such that the imaginary part of z is nonzero and a = z2 + z + 1 is real. Then a cannot take the value

 12

 34

 13

–1

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Solution

Let z = x + iy (y  0) then a = x2 – y2 + 2ixy + x + iy + 1 or a = (x2 – y2 + x + 1) + i (2xy + y)

Since a is real    Im(a) = 0    2xy + y = 0    2x = – 1 (as y  0)

Now,  a=(12)2y212+1=14y212+1=34y2

 a<34