Engineering
Mathematics
Conjugate Modulus and Argument of a Complex Number
Question

Let z be a complex number such that |z−iz+2i|=1  and  |z|=52. Then the value of |z + 3i| is :

72

10

154

23

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Solution

x2 + (y–1)2 = x2 + (y+2)2

– 2y + 1 = 4y + 4

6y = – 3 ⇒ y = – 1/2

x2+y2=254⇒x2=244=6⇒z=±6−i2

|z+3i|=6+254=494

|z+3i|=72