Engineering
Mathematics
Scalar Triple Product
Question

Let  PR=3i^+j^2k^  and  SQ=i^3j^4k^  determine diagonals of a parallelogram PQRS and PT=i^+2j^+3k^  be another vector. Then the volume of the parallelepiped determined by the vectors  PT,PQ  and  PS is

5

20

30

10

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Solution

 Given,   a+b=i^+2j^+3k^

 ba=i^3j^4k^

 a=i^+2j^+k^,  b=2i^j^3k^

 and  PT=i^+2j^+3k^

   volume=[abPT]=10