M–1L–2T3 θ are the dimensions of [T for time, θ for temperature]

Engineering

Physics

SI Units

Dimensions

Conduction of Heat

Question

M^–1L^–2T³ θ are the dimensions of [T for time, θ for temperature]

modulus of rigidity

coeffcient of thermal conductivity

coefficient of viscosity

thermal resistance

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$\frac{dQ}{dt} = \frac{kA}{ℓ} Δθ$

$\Rightarrow [k] = \frac{{ML}^{2} T^{- 3} \times L}{L^{2} \times θ} = {MLT}^{- 3} θ^{- 1}$

$R_{τh} = \frac{L}{kA} = \frac{L}{{MLT}^{- 3} θ^{- 1} \times L^{2}} = M^{- 1} L^{- 2} T^{3} θ$