Magnifying power of an astronomical telescope is 15. Then ratio of the focal length of the objective to the focal length of the eye piece is :

Foundation

Physics Foundation

Human Eye And Colorful World

Question

1.5

$\frac{1}{15}$

None

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magnifying power of telescope, M = 15

$∵ M = \frac{f_{0}}{f_{e}} = 15$

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