The reaction involves the addition of HBr to an alkene, following Markovnikov's rule. The hydrogen adds to the less substituted carbon, and the bromine adds to the more substituted carbon. The carbocation intermediate is stabilized by the adjacent phenyl ring, leading to the major product.

The major product is the bromoalkane where the bromine is attached to the tertiary carbon, which is benzylic and highly stabilized: $Ph-CH\left(CH3\right)-CH2-Br$.

Final Answer: The second option.