Me–CH2 – CH2OH Then :

Engineering

Chemistry

Carboxylic Acids

Oxidation of alcohol

Question

Me–CH₂ – CH₂OH $\overset{{KMnO}_{4} / H^{+}}{\to} (A) \overset{Red P + {Br}_{2}}{\to} (B) \overset{{NH}_{3} (Xs)}{\to} (C)$

Then :

Compound B is α - bromo acid

All of these

Compound A gives effervesence of CO₂ with NaHCO₃

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$Me - {CH}_{2} - {CH}_{2} OH \overset{{KMnO}_{4} / H^{\oplus}}{\to}$