Engineering
Physics
Moment of Inertia
Question

Moment of inertia of a body about a given axis is 1.5 kg m2. Initially the body is at rest. In order to produce a rotational kinetic energy of 1200 J, the angular acceleration of 20 rad/s2 must be applied about the axis for a duration of :

5 s

2 s

3 s

2.5 s

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Solution

KE = 12 Iω2 = 1200 (given)

⇒ ω = 40 rad/s

ω = ω0 + at

40 = 0 + (20) t

⇒ t = 2 sec.