No. of molecules present is 8 g of O2 are -

Foundation

Chemistry Foundation

Mole Concept and Calculation

Question

No. of molecules present is 8 g of O₂ are -

2.505 × 10²³

None

1.505 × 10²³

6.023 × 10²³

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∵ 32 g of O₂ contain = 6.023 × 10²³ molecules
∴ 8g of O₂will contain $= \frac{6 .023 \times 10^{23}}{32} \times 8$
= 1.505 × 10²³ molecules