Number of molecules present in 0.18 g H2O are -

Foundation

Chemistry Foundation

Mole Concept and Calculation

Question

Number of molecules present in 0.18 g H₂O are -

18 × 6.023 × 10²³

0.18 × 6.023 × 10²³

6.023 × 10²¹

6.023 × 10²³

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∴ 18 g of H₂O contains 6.023 × 10²³ molecules
∴ 0.18 g of H₂O will contains
$= \frac{6.023 \times 10^{23}}{18} \times 0.18$
= 6.023 × 10²¹ molecules