Number of moles of NH3 produced if 140 g of N2 reacts with 40 g of hydrogen. [Given % yield of reaction is 50%]

Engineering

Chemistry

Chemical Equation and Stoichiometric Calculation

Question

Number of moles of NH₃ produced if 140 g of N₂ reacts with 40 g of hydrogen.
[Given % yield of reaction is 50%]

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N₂ + 3H₂ $\overset{50 %}{\to}$ 2NH₃
140 g 40 g
= 5 mol = 20 mol
$∴$ Number of moles of NH₃ produced = $\frac{10}{2}$ = 5