One mole of a monatomic ideal gas is taken along two cyclic processes E → F → G → H and E → F → H → E as shown in the PV diagram. The processes involved are purely isochoric, isobaric, isothermal or adiabatic.Match the paths in List I with the magnitudes of the work done in List II and select the correct answer using the codes given below the lists.List IList II(P) G E(1) 160 P0 V0 ln2(Q) G H(2) 36 P0 V0(R) FH(3) 24 P0 V0 (S) F G(4) 31 P0 V0

Engineering

Physics

Thermodynamics

Cyclic Processes

Question

One mole of a monatomic ideal gas is taken along two cyclic processes E → F → G → H and E → F → H → E as shown in the PV diagram. The processes involved are purely isochoric, isobaric, isothermal or adiabatic.

Match the paths in List I with the magnitudes of the work done in List II and select the correct answer using the codes given below the lists.

List I	List II
(P) G $\to$ E	(1) 160 P₀ V₀ ln2
(Q) G $\to$ H	(2) 36 P₀ V₀
(R) F $\to$ H	(3) 24 P₀ V₀
(S) F $\to$ G	(4) 31 P₀ V₀

P → 4

Q → 3

R → 1

S → 2

P → 4

Q → 3

R → 2

S → 1

P → 1

Q → 3

R → 2

S → 4

P → 3

Q → 1

R → 2

S → 4

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$F \to G \to$ isotherm $\to$ 160P₀V₀ ln

32 P₀ V₀^5/3 = P₀ V^5/3

V_H = 8V₀

P₀V_G = 32P₀ × V0

V_G = 32 V₀

W_GE = P₀ × 31 V0

W_{F – G}= 32P₀V₀ ln $(\frac{32 V_{0}}{V_{0}})$ = 160P₀V₀ ln 2