One mole of a monatomic ideal gas undergoes four thermodynamic processes as shown schematically in the PV-diagram below. Among these four processes, one is isobaric, one is isochoric, one is isothermal and one is adiabatic. Match the processes mentioned in List-1 with the corresponding statements in List-II.
| List-I | List-II |
| (P) In process I | (1) Work done by the gas is zero |
| (Q) In process II | (2) Temperature of the gas remains unchanged |
| (R) In process III | (3) No heat is exchanged between the gas and its surroundings |
| (S) In process IV | (4) Work done by the gas is 6P0V0 |
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Process I : Adiabatic as negative of slope is greater i.e. z
Process IV : Isothermal process
Process III : Isochoric process
Process II : Isobaric process
Process I : No heat exchange
Process II : Work done = PDV
= 3P0 (3V0 – V0)
= 6P0V0
Process III : Work done is zero as there is no volume change
Process IV : Since isothermal process i.e. temp. remains unchanged.
Option (C)