Engineering
Physics
Straight Line Motion
Collision
Relative Motion
Question

One small piece of putty m is thrown down from point A with initial downwards velocity v. A second small piece of putty also of mass m is thrown up from point B at the same time but with initial velocity 2v. Point A is h meters above point B. The pieces of putty collide and stick together. Assume the collision point occurs while the second piece is still traveling upwards. How high above point B does the combined piece of putty reach? Take v = 8 m/s, g = 10 m/s2, h = 20 m, Express answer in cm.

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Solution
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Verified by Zigyan

Rel. v = 24

t for collision =2024=56

vA at collision = 8 + 10 56=8+506=986

vB = at collision = 16 – 10 56=96506=466

vA > vB
So putting moves down after collision.
Non height = dis moved by B hill collision

=ut+12at2=165612×10×2536=986.11cm