Engineering
Physics
Superposition of Simple Harmonic Motion
Basics of Simple Harmonic Motion
Question

Out of the statements given, which is/are correct ?

The amplitude of a resultant simple harmonic motion obtained by superposition of two simple harmonic motions along the same direction can be less than lesser of the amplitudes of the participating SHMs.

When two simple harmonic motions which are in phase and in perpendicular directions superpose then resulting motion will be SHM with same phase.

The combination of two simple harmonic motions of equal amplitude in perpendicular directions differing in phase by π/2 rad is a circular motion.

When two simple harmonic motions (with amplitudes A1 and A2) which are out of phase (that means phase difference p) and in perpendicular directions, superpose then resulting motion will be SHM with amplitude A12+A22.

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Solution
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A is correct as

Ar2=A12+A22+2A1A2cosφ=(A1−A2)2−2A1A2(1−cosφ)

B & C are correct as

R=x2+y2=A12+A22sin (ωt+φ)

D is correct as x = A sin (ωt + φ),

y = a cos (ωt + φ)

x2 + y2 = A2 is an equation of circular motion.