The image shows a right triangle with hypotenuse 10 and one leg 6. To find the other leg P, use the Pythagorean theorem: $a^2+b^2=c^2$. Here, $6^2+P^2={10}^2$. This simplifies to $36+P^2=100$. Solving gives $P^2=64$, so $P=8$.

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