Understanding the Reaction: Ozonolysis of Alkenes

This question involves predicting the product of ozonolysis for a given alkene. Ozonolysis is a reaction where alkenes are cleaved by ozone (O₃) to form carbonyl compounds (aldehydes or ketones).

Step 1: Analyze the Alkene Structure

The reactant is a cyclic alkene with a double bond. Based on the molecular structure shown, it is cyclopentene.

Structure: $Cyclopentene$

Step 2: Understand Ozonolysis Mechanism

Ozonolysis cleaves the double bond. Each carbon of the double bond becomes a carbonyl carbon:

If the carbon was bonded to two hydrogens (terminal alkene), it forms an aldehyde (R-CHO)
If the carbon was bonded to alkyl groups, it forms a ketone (R-CO-R')

Step 3: Apply to Cyclopentene

Cyclopentene has a double bond between two CH₂ groups in a five-membered ring. Cleaving this bond would open the ring and form a dialdehyde.

Reaction: $Cyclopentene + O_{3} \to OHC - ({CH}_{2}) 3 - CHO$

This gives pentanedial (a 5-carbon chain with aldehyde groups at both ends).

Step 4: Match with Options

Comparing with the provided images, the correct product is the dialdehyde: OHC-(CH₂)₃-CHO

Final Answer: $OHC - ({CH}_{2}) 3 - CHO$

Related Topics

Alkene Reactions
Oxidative Cleavage
Carbonyl Compounds
Cyclic Hydrocarbons

Key Formulae and Theory

General Ozonolysis Reaction: $R - CH = CH - R' + O_{3} \to R - CHO + R' - CHO$

For cyclic alkenes, the ring opens to form a chain with carbonyl end groups.