This is a nucleophilic substitution reaction where the cyanide ion (CN⁻) attacks the carbon adjacent to the bromine (Br) in the given bromoalkane. The bromine is a good leaving group, so it is substituted by the -CN group. This reaction is an example of an SN2 mechanism, which proceeds with inversion of configuration at the chiral carbon center.

The product is: $NC-{CH}_2-CH\left(C{H}_3\right)-C{H}_2-C{H}_3$

Final Answer: The second option.