Organic Reaction: Ozonolysis of Alkenes

This question involves ozonolysis of an alkene followed by reductive workup (Zn/H $O_{2}$ ). Ozonolysis cleaves carbon-carbon double bonds and produces carbonyl compounds.

Step 1: Analyze the Starting Compound

The reactant is a cyclic alkene with a double bond between two carbon atoms. The structure shows a 6-membered ring with one double bond.

Step 2: Understand Ozonolysis Mechanism

Ozonolysis cleaves the double bond completely. Each carbon of the double bond becomes a carbonyl carbon:

$R R_{1} C = C R_{2} R_{3} \to R R_{1} C = O + O = C R_{2} R_{3}$

Step 3: Apply to This Molecule

The double bond cleavage will produce two dicarbonyl compounds since both carbons are part of the ring structure. The products will be dialdehydes.

Step 4: Identify the Correct Product

The correct product is the dialdehyde where both carbonyl groups are aldehydes (-CHO), which corresponds to the third option.

Final Answer

The product is: Dialdehyde product

Related Topics

Alkene Reactions
Oxidative Cleavage Reactions
Carbonyl Chemistry
Cyclic Compound Reactivity

Important Formulae and Theory

General ozonolysis reaction: $R R_{1} C = C R_{2} R_{3} \to R R_{1} C = O + O = C R_{2} R_{3}$

Reductive workup (Zn/H $O_{2}$ ) prevents further oxidation of aldehydes to carboxylic acids.

Terminal alkenes produce formaldehyde (HCHO) as one product.