Engineering
Mathematics
Introduction to Determinants
Question

Prove that 1ωω2ωω21ω21ω=0

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Solution
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Solving given determinant, we get

[1(ω3 – 1) – ω(ω2 – ω2) + ω2(ω – ω4)]         .......  as (ω3 = 1)
⇒  [(1 – 1) – ω(0) + ω2(ω – ω)]
⇒  0 + 0 + 0
⇒  0
Hence proved
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