The given reaction involves the formation of a peptide bond between an amino acid derivative and an amine. Let's analyze the reaction step by step.

The reactant is $MeCOONa$ which is sodium acetate, and $HOCH_{2} CH_{2} NH_{2}$ which is 2-aminoethanol. Sodium acetate can act as a source of the acetate ion, and 2-aminoethanol has both an alcohol group and an amine group.

However, in organic synthesis, sodium carboxylates can undergo reactions to form amides when heated with amines, but typically this requires activation of the carboxylate. In this case, the presence of the hydroxyl group in 2-aminoethanol might facilitate an intramolecular reaction or act as a nucleophile, but the primary amine group is a better nucleophile.

Upon heating, sodium acetate and 2-aminoethanol can react to form an amide linkage. The carboxylate group from acetate attacks the amine group of 2-aminoethanol, leading to the formation of $MeCONHCH_{2} CH_{2} OH$ , which is N-(2-hydroxyethyl)acetamide. This compound has the structure where the acetyl group is attached to the nitrogen of the ethanolamine.

Now, looking at the options, the correct product is the one that shows this amide formation. The first option shows a structure with a carbonyl group attached to nitrogen and then to a CH₂CH₂OH group, which matches N-(2-hydroxyethyl)acetamide.

Step-by-step mechanism:

Step 1: The carboxylate ion (from MeCOONa) acts as a nucleophile and attacks the electrophilic carbon in the amine group? Actually, typically the amine attacks the carbonyl carbon. But since the carboxylate is not activated, it might require heat to proceed.

In reality, this reaction is similar to the formation of an amide from a carboxylic acid and amine, but here we have the sodium salt. Sodium carboxylates can react with amines upon heating to form amides, often with the loss of water, but in this case, no water is shown to be eliminated directly. However, the reaction likely involves dehydration.

Alternatively, the hydroxyl group might participate, but it is not necessary. The direct reaction between a carboxylate salt and an amine under heat can yield the amide.

Thus, the product is MeCONHCH₂CH₂OH.

Comparing with the options:

The first option has the structure: O=C(NCCO)CH3, which is correct.

The second option shows a five-membered ring, which would require intramolecular reaction, but that is not feasible here since the groups are on different molecules.

The third option shows an ester, which might form if the alcohol group attacked, but amines are better nucleophiles than alcohols, so amide formation is preferred.

Therefore, the correct answer is the first option: N-(2-hydroxyethyl)acetamide.

Related Topics

This question involves the reaction between a carboxylate salt and an amine to form an amide. Key topics include:

Amide formation reactions
Nucleophilic substitution at carbonyl carbon
Reactivity of amines versus alcohols

Formulae

The general reaction for amide formation from carboxylic acid and amine is:

RCOOH + R'NH_{2} \to RCONHR' + H_{2} O

With carboxylate salts, the reaction may proceed under heat.