Engineering
Chemistry
Hydrogen Spectrum
Question

Ratio of wavelength of series limit of Balmer and Pascher series for an atom is

4/9

2/9

9/4

3/2

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Solution

           1λ∞→2=R[14−1∞]                 .........(i)

and    1λ∞→3=R[19−1∞]                  .........(ii)

eg. (ii) and (i)

λ∞→2λ∞→3=1914=49