Engineering
Mathematics
Multiplication of Matrices
Symmetric and Skew Symmetric Matrices
Question

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Solution
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A[0amp;tanα/2,tanα/2,amp;0]
I+A=[1amp;00amp;1]+[0amp;tanα/2,tanα/2,amp;0]
=[1amp;tanα/2,tanα/2,amp;1]
IA=[cosα,,amp;sinα,,sinα,,amp;cosα,,]
=[[1amp;00amp;1][0amp;tanα/2,tanα/2,amp;0]]×[cosα,,amp;sinα,,sinα,,amp;cosα,,]
=[1amp;tanα/2,tanα/2,amp;1]×[cosα,,amp;sinα,,sinα,,amp;cosα,,]
=[cosα,+tanα/2sinα,,amp;sinα2+tanα/2cosα,,tanα/2cosα,+sinα,,amp;sinα,tanα/2+cosα,,]
=[1tanα,2,+tanα,2,,1+tan2α,2,,×2tanα,2,,amp;2tanα,2,+tanα,2,,1+tan2α,2,,tan3α,2,,2tanα,2,tanα,2,,1+tan2α,2,,tan3α,2,,amp;1tanα,2,+tanα,2,,1+tan2α,2,,×2tanα,2,,]
=[1amp;tanα/2,tanα/2,amp;1]
=I+A
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