Engineering
Physics
Physical Quantities
Question

Repeat

At t = τ , q = CV/2

Work done by the battery is half of the energy dissipated in the resistor

At t = 2τ, q = CV(1– e–2)

At t = , q = CV(1– e–1)

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Solution
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q = q0 (1 – e–t/t)

= CV(1 – e–2τ/τ)

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