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Engineering

Physics

Physical Quantities

Question

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Work done by the battery is half of the energy dissipated in the resistor

At t = 2τ, q = CV(1– e^–2)

At t = , q = CV(1– e^–1)

At t = τ , q = CV/2

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q = q₀ (1 – e^–t/t)

= CV(1 – e^–2τ/τ)