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Engineering

Physics

Physical Quantities

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108 N

96 N

120 N

150 N

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$g = \frac{GM}{R^{2}} = \frac{4 G}{3} \frac{{ρR}^{3}}{R^{2}} = \frac{4}{3} GρR$

$g'_{ρ} = \frac{g}{10} = 1$

$F = \int λdyg$

$= 10^{- 3} \times \int \frac{GM}{R^{2}} \times \frac{y}{R} dy$

$= 10^{- 3} \times 1 {\frac{y^{2}}{2 R} |}_{R / 5}^{R} = \frac{10^{- 3}}{2 R} [R^{2} - \frac{16 R^{2}}{25}]$

$= \frac{9}{25} \times \frac{R}{2} \times 10^{- 3}$

$= \frac{9}{25} \times 3 \times 10^{5} \times 10^{- 3} = 108 N$