S is a solid neutral conducting sphere. A point charge q of 1 × 10–6C is placed at point A. C is the centre of sphere and AB is a tangent. BC = 3m and AB = 4m.

Engineering

Physics

Electric Potential Energy and Electric Potential

Question

S is a solid neutral conducting sphere. A point charge q of 1 × 10^–6C is placed at point A. C is the centre of sphere and AB is a tangent. BC = 3m and AB = 4m.

The electric potential at B due to induced charges on the sphere is – 0.45 kV.

The electric potential of the conductor is 1.8 kV

The electric potential of the conductor is 2.25 kV

The electric potential at B due to induced charges on the sphere is 0.45 kV.

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AC = 5 m
V = $\frac{kq}{AC} = \frac{9 \times 10^{9} \times 1 \times 10^{- 6}}{5}$ = 1.8 × 10³ = 1.8 kV
V_B = (V_B)_{due to q} + (V_B)_i (V_B)_i = Potential at B due to induced charge
$∴$ 1.8 × 10³ = $\frac{kq}{AB}$ + (V_B)_i
1.8 × 10³ = 2.25 × 10³ + (V_B)_i
(V_B)_i = –0.45 kV